URI Online Judge Solution 1074 Even or Odd – Solution in C, C++, Java, Python and C#

URI Online Judge Solution URI Solution -Beginner

URI Online Judge Solution 1074 Even or Odd – Solution in C, C++, Java, Python and C#

URI Online Judge Solution 1074 Even or Odd | Beginner
URI Problem Link – https://www.urionlinejudge.com.br/judge/en/problems/view/1074

Problem Name: 1074 Even or Odd
Problem Number : URI – 1074 Even or Odd
Online Judge : URI Online Judge Solution
Category: Beginner
Solution Language : C,C plus plus, java, python, c#(c sharp)

URI Solution 1074 Even or Odd Code in C:

#include <stdio.h>
int main( ){

int N, i, x;
scanf("%d", &N);
for( i = 1; i <= N; i++){
scanf("%d", &x);
if(x == 0){
printf("NULLn");
}else if(x % 2 == 0){
if(x > 0){
printf("EVEN POSITIVEn");
}else{
printf("EVEN NEGATIVEn");
}

}else{
if(x > 0){
printf("ODD POSITIVEn");
}else{
printf("ODD NEGATIVEn");
}
}

}
}

URI Solution 1074 Even or Odd Code / URI 1074 solution in CPP:

#include <iostream>

using namespace std;

int main()
{
int n, x;

cin >> n;

for (int i = 0; i < n; ++i)
{
cin >> x;

if(x == 0){
cout << "NULL" << endl;
}else if(x % 2 == 0){
if(x > 0){
cout << "EVEN POSITIVE" << endl;
}else{
cout << "EVEN NEGATIVE" << endl;
}

}else{
if(x > 0){
cout << "ODD POSITIVE" << endl;
}else{
cout << "ODD NEGATIVE" << endl;
}

}
}

return 0;
}

URI Solution 1074 Even or Odd Code / URI 1074 solution in Java:

/** URI - 1074 by Java
* Author - Maniruzzaman Akash
*/

import java.util.*;

public class Main {

public static void main(String[] args){

int N, i, x;
Scanner sc = new Scanner(System.in);
N = sc.nextInt();
for( i = 1; i <= N; i++){
x = sc.nextInt();
if(x == 0){
System.out.printf("NULLn");
}else if(x % 2 == 0){
if(x > 0){
System.out.printf("EVEN POSITIVEn");
}else{
System.out.printf("EVEN NEGATIVEn");
}

}else{
if(x > 0){
System.out.printf("ODD POSITIVEn");
}else{
System.out.printf("ODD NEGATIVEn");
}
}

}

}

}

URI Solution 1074 Even or Odd Code / URI 1074 solution in  Python:

l=[]
a=int(input())
for n in range(1,(a+1)):
l.append(int(input()))
for n in l:
if (n%2!=0)and (n0):
print("ODD POSITIVE")
if(n%2==0)and(n0):
print("EVEN POSITIVE")

URI Solution 1074 Even or Odd Code / URI 1074 solution in  C# (C Sharp):

Demonstration:

This is something pretty conditional code. If happens this print this or others. Nothing is hard here. Try to do with yourself.

Run Live: (Give the input in StdIn Inputs and see result live if it is working or not)

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