URI Online Judge Solution 1075 Remaining 2 Solution in C, C++, Java, Python and C#-

URI Online Judge Solution 1075 Remaining 2  Solution in C, C++, Java, Python and C#- 

URI Online Judge Solution 1075 Remaining 2  | Beginner
URI Problem Link – https://www.urionlinejudge.com.br/judge/en/problems/view/1075

Problem Name: 1075 Remaining 2
Problem Number : URI – 1075 Remaining 2
Online Judge : URI Online Judge Solution
Category: Beginner
Solution Language : C,C plus plus, java, python, c#(c sharp)

URI Solution 1075 Remaining 2  Code in C:

#include <stdio.h>

int main()
{
 int n, i;

 scanf("%i", &n);

 for (i = 1; i <= 10000; ++i)
 {
  if(i % n == 2){
   printf("%in", i);
  }
 }

 return 0;
}

URI Solution 1075 Remaining 2  Code / URI 1075 Remaining 2  solution in CPP:

#include <cstdio>
int main()
{
 int n;

 scanf("%i", &n);

 for (int i = 1; i <= 10000; ++i)
 {
  if(i % n == 2){
   printf("%in", i);
  }
 }

 return 0;
}

import java.util.Scanner;

public class Main {

 public static void main(String[] args) {

  int N;
  Scanner input =new Scanner(System.in);
  
  N =input.nextInt();
  for (int i = 0; ((N*i) + 2) < 10000; i++) {
   System.out.print((N*i) + 2+"n");
  }
 }
}

URI Solution 1075 Remaining 2  Code / URI 1075 Remaining 2  solution in  C# (C Sharp):

Demonstration:

Just implement this in coding. Since having any problem just put a comment below. Thanks

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