# URI Online Judge Solution 1075 Remaining 2 Solution in C, C++, Java, Python and C#-

### URI Online Judge Solution 1075 Remaining 2  Solution in C, C++, Java, Python and C#-

URI Online Judge Solution 1075 Remaining 2  | Beginner

Problem Name: 1075 Remaining 2
Problem Number : URI – 1075 Remaining 2
Online Judge : URI Online Judge Solution
Category: Beginner
Solution Language : C,C plus plus, java, python, c#(c sharp)

### URI Solution 1075 Remaining 2  Code in C:

``#include <stdio.h>int main(){ int n, i; scanf("%i", &n); for (i = 1; i <= 10000; ++i) {  if(i % n == 2){   printf("%in", i);  } } return 0;}``

### URI Solution 1075 Remaining 2  Code / URI 1075 Remaining 2  solution in CPP:

``#include <cstdio>int main(){ int n; scanf("%i", &n); for (int i = 1; i <= 10000; ++i) {  if(i % n == 2){   printf("%in", i);  } } return 0;}``

### URI Solution 1075 Remaining 2  Code / URI 1075 Remaining 2   solution in Java:

``import java.util.Scanner;public class Main { public static void main(String[] args) {  int N;  Scanner input =new Scanner(System.in);    N =input.nextInt();  for (int i = 0; ((N*i) + 2) < 10000; i++) {   System.out.print((N*i) + 2+"n");  } }}``

### URI Solution 1075 Remaining 2  Code / URI 1075 Remaining 2  solution in  C# (C Sharp):

Demonstration:

Just implement this in coding. Since having any problem just put a comment below. Thanks

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