URI Online Judge Solution 1073 Even Square – Solution in C, C++, Java, Python and C#

URI Online Judge Solution URI Solution -Beginner

URI Online Judge Solution 1073 Even Square – Solution in C, C++, Java, Python and C#

URI Online Judge Solution 1073 Even Square | Beginner
URI Problem Link – https://www.urionlinejudge.com.br/judge/en/problems/view/1073

Problem Name: 1073 Even Square
Problem Number : URI – 1073 Even Square
Online Judge : URI Online Judge Solution
Category: Beginner
Solution Language : C,C plus plus, java, python, c#(c sharp)

1073 Even Square

URI Solution 1073 Even Square Code in C:

#include <stdio.h>
int main()
{
int n, i;

scanf("%d", &n);

for ( i = 1; i <= n; ++i)
{
if(i % 2 == 0){
printf("%d^2 = %dn", i,(i * i));
}
}

return 0;
}

URI Solution 1073 Even Square Code / URI 1002 solution in CPP:

#include <iostream>

using namespace std;

int main(int argc, const char * argv[])
{
int N, i;

cin >> N;

for(i = 1; i <= N; i++) {
if(i%2 == 0) {
cout << i << "^2 = " << i*i << endl;
}
}

return 0;
}

URI Solution 1073 Code / URI 1073 Even Square  solution in Java:


/**
6
2^2 = 4
4^2 = 16
6^2 = 36

*/
import java.util.Scanner;
import java.io.IOException;

public class Main {

public static void main(String[] args) {

int N;
Scanner input =new Scanner(System.in);
N =input.nextInt();


for (int i = 2; i <= N; i+= 2) {
System.out.print(i+"^2 = "+(i*i)+"n");
}

}

}

URI Solution 1073 Even Square Code / URI 1073 solution in  Python:

a=int(input())
for n in range(1,(a+1)):
if (n%2==0):
print("%d^2 = %d" %(n, n**2))

URI Solution 1073Code / URI 1073 Even Square solution in  C# (C Sharp):

Demonstration:

  1. Take a loop upto n
  2. Inside loop if that is divisble by 2 then
  3. square it and print it. Main Lines are this-

 for ( i = 1; i <= n; ++i)
{
if(i % 2 == 0){
printf("%d^2 = %dn", i,(i * i));
}
}

Just implement this in coding. Since having any problem just put a comment below. Thanks

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