URI Online Judge Solution 1067 Odd Numbers – Solution in C, C++, Java, Python and C#

URI Online Judge Solution URI Solution -Beginner

URI Online Judge Solution 1067 Odd Numbers – Solution in C, C++, Java, Python and C#

URI Online Judge Solution 1067 Odd Numbers  | Beginner
URI Problem Link – https://www.urionlinejudge.com.br/judge/en/problems/view/1067

Problem Name: 1067 Odd Numbers
Problem Number : URI – 1067 Odd Numbers
Online Judge : URI Online Judge Solution
Category: Beginner
Solution Language : C,C plus plus, java, python, c#(c sharp)

URI Online Judge Solution 1067 Odd Numbers - Solution in C, C++, Java, Python and C#

URI 1067 Odd Numbers  Code in C / URI 1067 Odd Numbers  solution in C:

Run URI 1067 code in C language in Live code editor:

Please to check live result give the predefined input as 8 and you must see the output like this:

Input Sample Output Sample
8 1
3
5
7

Run:

URI 1067 Odd Numbers  Code in C++ / URI 1067 Odd Numbers  solution in CPP:

#include <cstdio>

int
main()
{

int
n;

scanf("%i", &n);

for
(int i = 0; i <= n; ++i)
{

if
(i % 2 == 1)
printf("%in", i);
}


return
0;
}

URI 1067 Odd Numbers  Code in java/ URI 1067 Odd Numbers  solution in Java:

import java.util.Scanner;
public class
Main {

public static
void main(String[] args){
int
X;
Scanner input =new Scanner(System.in);
X = input.nextInt();
System.out.print(1+"n");
for
(int i = 1; i < X-1; i+=2) {
int
oddNumber = i + 2;
System.out.print(oddNumber+"n");
}
}

}

URI 1067 Odd Numbers  Code in Python / URI 1067 Odd Numbers  solution in Python:

numero = int(raw_input())

i = 1

while
(i <= numero):
if
(i%2 != 0):
print i

i = i + 1

URI Solution 1067 Odd Numbers  Code / URI 1067 Odd Numbers  solution in  C# (C Sharp):

Demonstration:

Just implement this in coding. Since having any problem just put a comment below. Thanks

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