URI Online Judge Solution 1066 Even, Odd, Positive and Negative – Solution in C, C++, Java, Python and C#

URI Online Judge Solution 1066 Even, Odd, Positive and Negative – Solution in C, C++, Java, Python and C#

URI Online Judge Solution 1066 Even, Odd, Positive and Negative  | Beginner
URI Problem Link – https://www.urionlinejudge.com.br/judge/en/problems/view/1066

Problem Name: 1066 Even, Odd, Positive and Negative
Problem Number : URI – 1066 Even, Odd, Positive and Negative
Online Judge : URI Online Judge Solution
Category: Beginner
Solution Language : C,C plus plus, java, python, c#(c sharp)

URI 1066 Even, Odd, Positive and Negative  Code in C / URI 1066 solution in C:

#include <stdio.h>

int main()
{
 int n, i;
 int pos = 0, neg = 0, par = 0, im = 0;
 
 for(i = 0; i < 5; ++i)
 {
  scanf("%d", &n);
  if(n > 0){
   pos++;
  }else{
   if(n != 0){
    neg++;
   }
  }
  
  if(n % 2 == 0){
   par++;
  }else{
   im++;
  }
 }
 
 printf("%d valor(es) par(es)n", par);
 printf("%d valor(es) impar(es)n", im);
 printf("%d valor(es) positivo(s)n", pos);
 printf("%d valor(es) negativo(s)n", neg);
 
 return 0;
}

Run URI 1066 code in C language with giving the inputs:

Input is:

 Please copy ans paste this input in the input bar of jdoodle

Run:

URI 1066 Even, Odd, Positive and Negative  Code in C++ / URI 1066 solution in CPP:

#include <iostream>

using namespace std;

int main()
{
 int n;
 int pos = 0, neg = 0, par = 0, im = 0;
 
 for(int i = 0; i < 5; ++i)
 {
  cin >> n;
  if(n > 0){
   pos++;
  }else{
   if(n != 0){
    neg++;
   }
  }
  
  if(n % 2 == 0){
   par++;
  }else{
   im++;
  }
 }
 
 cout << par << " valor(es) par(es)" << endl;
 cout << im << " valor(es) impar(es)" << endl;
 cout << pos << " valor(es) positivo(s)" << endl;
 cout << neg << " valor(es) negativo(s)" << endl;
 
 return 0;
}

import java.util.Scanner;

public class Main {
 
    public static void main(String[] args) {
 
        int X, even = 0,odd = 0,positive = 0,negative = 0;
  Scanner input =new Scanner(System.in);
  for (int i = 1; i <= 5; i++) {
   X = input.nextInt();
   if (X % 2 == 0) {
    even += 1;
   }
   if (X % 2 != 0) {
    odd += 1;
   }
   if (X > 0) {
    positive += 1;
   }
   if (X < 0) {
    negative += 1;
   }
   
  }
  System.out.print(even+" valor(es) par(es)n");
  System.out.print(odd+" valor(es) impar(es)n");
  System.out.print(positive+" valor(es) positivo(s)n");
  System.out.print(negative+" valor(es) negativo(s)n");
 
    }
 
}

Run URI 1065 code in Java language in a real time code editor:

lista = []

i = 0
while i < 5:
 numero = int(raw_input())
 lista.append(numero)
 i = i +1

i = 0
pares = 0
impares = 0
positivos = 0
negativos = 0
while(i < len(lista)):
 if(lista[i] %2 == 0):
  pares = pares + 1
 elif(lista[i] %2 != 0):
  impares = impares + 1
  
 if(lista[i] > 0):
  positivos = positivos + 1
 elif(lista[i] < 0):
  negativos = negativos + 1
 
 i = i +1
 
 
print "%d valor(es) par(es)" %pares
print "%d valor(es) impar(es)" %impares
print "%d valor(es) positivo(s)" %positivos
print "%d valor(es) negativo(s)" %negativos

URI Solution 1066 Even, Odd, Positive and Negative  Code / URI 1066 solution in  C# (C Sharp):

Demonstration:

Just implement this in coding. Since having any problem just put a comment below. Thanks

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