URI Online Judge Solution 1066 Even, Odd, Positive and Negative – Solution in C, C++, Java, Python and C#

URI Online Judge Solution URI Solution -Beginner

URI Online Judge Solution 1066 Even, Odd, Positive and Negative – Solution in C, C++, Java, Python and C#

URI Online Judge Solution 1066 Even, Odd, Positive and Negative  | Beginner
URI Problem Link – https://www.urionlinejudge.com.br/judge/en/problems/view/1066

Problem Name: 1066 Even, Odd, Positive and Negative
Problem Number : URI – 1066 Even, Odd, Positive and Negative
Online Judge : URI Online Judge Solution
Category: Beginner
Solution Language : C,C plus plus, java, python, c#(c sharp)

URI 1066 Even, Odd, Positive and Negative  Code in C / URI 1066 solution in C:

#include <stdio.h>

int
main()
{

int
n, i;
int
pos = 0, neg = 0, par = 0, im = 0;

for
(i = 0; i < 5; ++i)
{

scanf("%d", &n);
if
(n > 0){
pos++;
}
else{
if
(n != 0){
neg++;
}
}


if
(n % 2 == 0){
par++;
}
else{
im++;
}
}


printf("%d valor(es) par(es)n", par);
printf("%d valor(es) impar(es)n", im);
printf("%d valor(es) positivo(s)n", pos);
printf("%d valor(es) negativo(s)n", neg);

return
0;
}

Run URI 1066 code in C language with giving the inputs:

Input is:

 Please copy ans paste this input in the input bar of jdoodle

Input Sample Output Sample
-5
0
-3
-4
12
3 valor(es) par(es)
2 valor(es) impar(es)
1 valor(es) positivo(s)
3 valor(es) negativo(s)

Run:

URI 1066 Even, Odd, Positive and Negative  Code in C++ / URI 1066 solution in CPP:

#include <iostream>

using namespace
std;

int
main()
{

int
n;
int
pos = 0, neg = 0, par = 0, im = 0;

for
(int i = 0; i < 5; ++i)
{

cin >> n;
if
(n > 0){
pos++;
}
else{
if
(n != 0){
neg++;
}
}


if
(n % 2 == 0){
par++;
}
else{
im++;
}
}


cout << par << " valor(es) par(es)" << endl;
cout << im << " valor(es) impar(es)" << endl;
cout << pos << " valor(es) positivo(s)" << endl;
cout << neg << " valor(es) negativo(s)" << endl;

return
0;
}

URI 1066 Even, Odd, Positive and Negative  Code in java/ URI 1066 solution in Java:

import java.util.Scanner;

public class
Main {

public static
void main(String[] args) {

int
X, even = 0,odd = 0,positive = 0,negative = 0;
Scanner input =new Scanner(System.in);
for
(int i = 1; i <= 5; i++) {
X = input.nextInt();
if
(X % 2 == 0) {
even += 1;
}

if
(X % 2 != 0) {
odd += 1;
}

if
(X > 0) {
positive += 1;
}

if
(X < 0) {
negative += 1;
}

}

System.out.print(even+" valor(es) par(es)n");
System.out.print(odd+" valor(es) impar(es)n");
System.out.print(positive+" valor(es) positivo(s)n");
System.out.print(negative+" valor(es) negativo(s)n");

}

}

Run URI 1065 code in Java language in a real time code editor:

URI 1066 Even, Odd, Positive and Negative  Code in Python / URI 1066 solution in Python:

lista = []

i = 0
while
i < 5:
numero = int(raw_input())
lista.append(numero)
i = i +1

i = 0
pares = 0
impares = 0
positivos = 0
negativos = 0
while
(i < len(lista)):
if
(lista[i] %2 == 0):
pares = pares + 1
elif(lista[i] %2 != 0):
impares = impares + 1

if
(lista[i] > 0):
positivos = positivos + 1
elif(lista[i] < 0):
negativos = negativos + 1

i = i +1


print "%d valor(es) par(es)" %pares
print "%d valor(es) impar(es)" %impares
print "%d valor(es) positivo(s)" %positivos
print "%d valor(es) negativo(s)" %negativos

URI Solution 1066 Even, Odd, Positive and Negative  Code / URI 1066 solution in  C# (C Sharp):

Demonstration:

Just implement this in coding. Since having any problem just put a comment below. Thanks

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