URI Online Judge Solution 1040 Average 3 – Solution in C, C++, Java, Python and C#

URI Online Judge Solution 1040 Average 3 – Solution in C, C++, Java, Python and C#

URI Online Judge Solution 1040 Average 3 | Beginner
URI Problem Link – https://www.urionlinejudge.com.br/judge/en/problems/view/1040

Problem Name: 1040 Average 3 solution
Problem Number : URI – 1040 Average 3 code
Online Judge : URI Online Judge Solution
Category: Beginner
Solution Language : C,C plus plus, java, python, c#(c sharp)

URI 1040 Average 3 Code in C / URI 1040 Average 3  solution in C:

#include <stdio.h>
int main()
{
    double a, b, c, d, last, m;
    scanf("%lf %lf %lf %lf", &a, &b, &c, &d);
    m = (a * 2 + b * 3 + c * 4 + d) / 10;
    printf("Media: %.1fn", m);
    if (m >= 7.0){
        printf("Aluno aprovado.n");
    }
    else if (m >= 5.0)
    {
        printf("Aluno em exame.n");
        scanf("%lf", &last);
        printf("Nota do exame: %.1fn", last);
        if (last + m / 2.0 > 5.0){
            printf("Aluno aprovado.n");
        }
        else{
            printf("Aluno reprovado.n");
        }
        printf("Media final: %.1fn", (last + m ) / 2.0);
    }
    else{
        printf("Aluno reprovado.n");
    }
    return 0;
}

URI 1040 Average 3 Code in C++ / URI 1040 Average 3 solution in CPP:

#include <cstdio>

#define SC1(a) scanf("%f", &a)
#define SC4(a, b, c, d) scanf("%f %f %f %f", &a, &b, &c, &d)

using namespace std;

int main(int argc, char const *argv[])
{
 float a, b, c, d, m, f;

 SC4(a, b, c, d);
 a = (a * 20)/100;
 b = (b * 30)/100;
 c = (c * 40)/100;
 d = (d * 10)/100;
 m = a + b + c + d;

 if(m >= 7.0){
  printf("Media: %.1fnAluno aprovado.n", m);
 }else if(m < 5.0){
  printf("Media: %.1fnAluno reprovado.n", m);
 }else{
  SC1(f);
  printf("Media: %.1fnAluno em exame.nNota do exame: %.1fn", m, f);
  if ((m + f) / 2 < 5.0) printf("Aluno reprovado.nMedia final: %.1fn", (m + f) / 2);
  else printf("Aluno aprovado.nMedia final: %.1fn", (m + f) / 2);
 }

 return 0;
}

import java.io.IOException;
import java.util.Scanner;
 
public class Main {
 
    public static void main(String[] args) throws IOException {
 
        
  float N1, N2, N3, N4,average,N5,recalaverage;
  Scanner input =new Scanner(System.in);
  N1 =input.nextFloat();
  N2 =input.nextFloat();
  N3 =input.nextFloat();
  N4 =input.nextFloat();
  
  average =((N1 * 2)+(N2 * 3)+( N3 * 4)+(N4 * 1))/10;
  
  if (average >= 7.0) {
   
    System.out.printf("Media: %.1fn",average);
    System.out.print("Aluno aprovado.n");
    
  }
  
  else if (average >= 5.0 && average <= 6.9) {
   
   System.out.printf("Media: %.1fn",average);
   System.out.print("Aluno em exame.n");
   N5 =input.nextFloat();
   System.out.printf("Nota do exame: %.1fn",N5);
   recalaverage =(average + N5) / 2;
   
   if (recalaverage >= 5.0) {
    System.out.print("Aluno aprovado.n");
    
   }else {
    System.out.print("Aluno reprovado.n");
    
   }
   
   System.out.printf("Media final: %.1fn",recalaverage);
   
  }
  
  else if (average < 5.0) {
   
   System.out.printf("Media: %.1fn",average);
   System.out.print("Aluno reprovado.n");
   
  }
 
    }
 
}

URI Solution 1040 Average 3 Code / URI 1040 Average 3 solution in  C# (C Sharp):

Demonstration:

Just implement this in coding. Since having any problem just put a comment below. Thanks

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