URI Online Judge Solution 1038 Snack – Solution in C, C++, Java, Python and C#

URI Online Judge Solution 1038 Snack – Solution in C, C++, Java, Python and C#

URI Online Judge Solution 1038 Snack | Beginner
URI Problem Link – https://www.urionlinejudge.com.br/judge/en/problems/view/1038

Problem Name: 1038 Snack Solution
Problem Number : URI – 1038 Snack Code
Online Judge : URI Online Judge Solution
Category: Beginner
Solution Language : C,C plus plus, java, python, c#(c sharp)

URI 1038 Snack Code in C / URI 1038 Snack solution in C:

#include<stdio.h>
int main()
{
    int X, Y;
    float price = 0;

    scanf("%d %d", &X, &Y);
    if (X == 1)
    {
        price  = (float) (4.00 * Y);
    }
    else if (X == 2)
    {
        price  = (float) (4.50 * Y);
    }
    else if (X == 3)
    {
        price  = (float) (5.00 * Y);
    }
    else if (X == 4)
    {
        price  = (float) (2.00 * Y);
    }
    else if (X == 5)
    {
        price  = (float) (1.50 * Y);
    }

    printf("Total: R$ %.2fn",price);

}

URI 1038 Snack Code in C++ / URI 1038 Snack solution in CPP:

#include <iostream>
#include <iomanip>

using namespace std;

int main()
{
 int t;
 float q;

 cin >> t >> q;

 if(t == 1){
  q *= 4.0; 
 }else if(t == 2){
  q *= 4.5;
 }else if(t == 3){
  q *= 5.0;
 }else if(t == 4){
  q *= 2.0;
 }else{
  q *= 1.5;
 }

 cout << "Total: R$ " << setprecision(2) <<  fixed << q << endl;

 return 0;
}

import java.io.IOException;
import java.util.Scanner;

public class Main {
 
    public static void main(String[] args) throws IOException {
 
       int X, Y;
  float price = 0;
  
  Scanner input = new Scanner(System.in);
  X = input.nextInt();
  Y = input.nextInt();
  if (X == 1) {
   price  = (float) (4.00 * Y);
  }else if (X == 2) {
   price  = (float) (4.50 * Y);
  }else if (X == 3) {
   price  = (float) (5.00 * Y);
  }else if (X == 4) {
   price  = (float) (2.00 * Y);
  }else if (X == 5) {
   price  = (float) (1.50 * Y);
  }
  
  System.out.printf("Total: R$ %.2fn",price);
 
    }
 
}

URI Solution 1038 Snack Code / URI 1038 Snack solution in  C# (C Sharp):

Demonstration:

Just implement this in coding. Since having any problem just put a comment below. Thanks

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