URI Online Judge Solution 1025 Where is the Marble? – Solution in C, C++, Java, Python and C#

URI Online Judge Solution 1025 Where is the Marble?  – Solution in C, C++, Java, Python and C#

URI Online Judge Solution 1025 Where is the Marble? | Beginner
URI Problem Link – https://www.urionlinejudge.com.br/judge/en/problems/view/1025

Problem Name: 1025 Where is the Marble code
Problem Number : URI – 1025 Where is the Marble solution
Online Judge : URI Online Judge Solution
Category: Beginner
Solution Language : C,C plus plus, java, python, c#(c sharp)

URI 1025 problem simple input output:

URI Solution 1025 Where is the Marble? Code in C++ / URI 1025 in CPP:

#include <cstdio>
#include <vector>
#include <algorithm>
using namespace std;

int main()
{
 int n, q, x, cases = 1, sizeR;
 vector<int> m; vector<int> r;
 pair<vector<int>::iterator, vector<int>::iterator> it;

 while(scanf("%i %i", &n, &q) && (n || q))
 {
  m.clear(); r.clear();

  for (int i = 0; i < n; ++i)
  {
   scanf("%i", &x);
   m.push_back(x);
  }

  for (int i = 0; i < q; ++i)
  {
   scanf("%i", &x);
   r.push_back(x);
  }

  sort(m.begin(), m.end()); 
  printf("CASE# %i:n", cases);
  sizeR = r.size();

  for (int i = 0; i < sizeR; ++i)
  {
   if(binary_search(m.begin(), m.end(), r[i])){
    it = equal_range(m.begin(), m.end(), r[i]);
    printf("%i found at %lin", r[i], (it.first - m.begin()) + 1);
    //std::cout <<resultados[a]<<" found at "<< (it.first - marmores.begin())+1<<endl;
   }else{
    printf("%i not foundn", r[i]);
    //cout <<resultados[a]<<" not found"<<endl;
   }
  }

  cases++;
 }

 return 0;
}

URI Solution 1025 Where is the Marble? Code / URI 1025solution in CPP:

URI Solution 1025 Where is the Marble? Code / URI 1025solution in  C# (C Sharp):

Demonstration:

Just implement this in coding. Since having any problem just put a comment below. Thanks

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