URI Online Judge Solution Data Structure | 1252 – Sort sort and sort
URI Online Judge Solution SQL | 1252 Sort sort and sort | Beginner
URI Problem Link – URI Data Structure | 1252 Sort sort and sort Link
Problem Name: Data Structure | Sort sort and sort
Problem Number : URI – Data Structure | 1252 Sort sort and sort
Online Judge : URI Online Judge Solution
Category: Data Structure
Solution Language : Data Structure
URI Online Judge Solution 1252 – Data Structure | 1252 – Sort sort and sort: Using C++
#include<bits/stdc++.h>
using namespace std;
int m;
bool comp (int a, int b){
if (b%m == a%m)
if(abs(a)%2 ==abs(b)%2){
if (a%2 != 0){
return a > b;
}else{
return b > a;
}
}
return abs(a)%2 > abs(b)%2;
}
return a%m < b%m;
}
int main()
{
int n;
while(cin>>n>>m&&n&&m){
int a[n];
for(int i=0;i<n;i++)
{
cin>>a[i];
}
sort(a,a+n,comp);
cout<<n<<" "<<m<<endl;
for(int i=0;i<n;i++)
cout<<a[i]<<endl;
}
printf("0 0n");
}
URI Online Judge Solution 1252 – Data Structure | 1252 – Sort sort and sort: Using C Language
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
#include <string.h>
#include <iostream>
#include <algorithm>
using namespace std;
int M;
bool comp (int a, int b){
if (b%M == a%M){ /// retorna primeiro os impares e depois os pares;
if(abs(a)%2 ==abs(b)%2){ ///comparando dois pares ou dois impares
if (a%2 != 0){ ///impares
return a > b;
}else{ ///a e b s?o pares
return b > a;
}
}
return abs(a)%2 > abs(b)%2; /// impares antes dos pares
}
return a%M < b%M;
}
int main()
{
int N, cont;
scanf("%d", &N);
scanf("%d", &M);
while(N!=0 && M!=0)
{
int vetor[N];
printf("%d %dn", N, M);
for(cont=0;cont<N;cont++){
scanf("%d", &vetor[cont]);
}
sort(vetor,vetor+N,comp);
for(cont=0;cont<N;cont++){
printf("%dn", vetor[cont]);
}
scanf("%d", &N);
scanf("%d", &M);
}
printf("0 0n");
return 0;
}
Demonstration:
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