# UVA Solution 484 – The Department of Redundancy Department – Code in C/cpp

### UVA Solution  484 – The Department of Redundancy Department – Volume 4

UVA Online Judge Solution  484 – The Department of Redundancy Department | Volume 4
UVA Problem Link –  484 – The Department of Redundancy Department

Problem Name:  484 – The Department of Redundancy Department
Problem Number : UVA –  484 – The Department of Redundancy Department
Online Judge : UVA Online Judge Solution
Volume: 4
Solution Language : C, C plus plus

### UVA Solution  484 – The Department of Redundancy Department Code in C/CPP:

#include<stdio.h>
#include<string.h>
#define Mod 100000
#define MaxL 1000000
int HASH[Mod], size;
typedef struct
{
int
v, time, next;
}
C;
C Node[MaxL];
int
insHash(int v) {
int
m = ((v%Mod)+Mod)%Mod;
int
now = HASH[m], pre = 0;
while
(now) {
if
(Node[now].v < v)
pre = now, now = Node[now].next;
else if
(Node[now].v == v) {
Node[now].time++;return 1;
}
else {
break
;
}
}

size++;
if
(!pre) HASH[m] = size;
else
Node[pre].next = size;
Node[size].v = v, Node[size].time = 1;
Node[size].next = now;
return
0;
}

int
main() {
int
n, i;
memset(HASH, 0, sizeof(HASH));
size = 0;
while
(scanf("%d", &n) == 1)
insHash(n);
for
(i = 1; i <= size; i++)
printf("%d %dn", Node[i].v, Node[i].time);
return
0;
}

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