UVA Solution 453 – Intersecting Circles – Volume 4

UVA Onilne Judge Solution UVA-Volume 4

UVA Solution 453 – Intersecting Circles – Volume 4

UVA Online Judge Solution 453 – Intersecting Circles | Volume 4
UVA Problem Link –

Problem Name: 453 – Intersecting Circles solution
Problem Number : UVA – 453 – Intersecting Circles solution
Online Judge : UVA Online Judge Solution
Volume: 4
Solution Language : C plus plus

UVA Online Judge Solution, UVA OJ Solution list, UVA Problems Solution, UVA solver, UVA all problem solution list- UVA Solution 453 - Intersecting Circles - Volume 4

UVA Solution 453 – Intersecting Circles Code in CPP:

#include <stdio.h>
#include <math.h>
#include <algorithm>
using namespace std;
struct
Cir {
double
x, y, r;
int
scan() {
return
scanf("%lf %lf %lf", &x, &y, &r) == 3;
}
};

#define eps 1e-6
struct Pt {
double
x, y;
bool
operator<(const Pt other) const {
if
(fabs(x-other.x) < eps)
return
y < other.y;
return
x < other.x;
}
};

int
IntersectCir(Cir A, Cir B, Pt v[]) { // Pt v[] result buffer
double disAB = sqrt((A.x-B.x)*(A.x-B.x)+(A.y-B.y)*(A.y-B.y));
if
(fabs(disAB) < eps && fabs(A.r-B.r) < eps) {
if
(A.r < eps) {
v[0].x = A.x;
v[0].y = A.y;
return
1;
}

return
0;
}

if
(A.r+B.r+eps < disAB || A.r+disAB+eps < B.r || B.r+disAB+eps < A.r) {
return
-1;
}

double
x, y, vx, vy;
vx = B.x - A.x;
vy = B.y - A.y;
if
(fabs(disAB-A.r-B.r) < eps || fabs(A.r-disAB-B.r) < eps ||
fabs(B.r-A.r-disAB) < eps) {
if
(fabs(disAB-A.r-B.r) < eps) { // (A)(B)
v[0].x = A.x+vx*A.r/(A.r+B.r);
v[0].y = A.y+vy*A.r/(A.r+B.r);
}
else {
if
(A.r < B.r) { //((A)B)
v[0].x = A.x-vx*A.r/(B.r-A.r);
v[0].y = A.y-vy*A.r/(B.r-A.r);
}
else { //((B)A)
v[0].x = B.x+vx*B.r/(A.r-B.r);
v[0].y = B.y+vy*B.r/(A.r-B.r);
}
}

return
1;
}

double
theta = acos((A.r*A.r+disAB*disAB-B.r*B.r)/2/A.r/disAB);
double
rvx, rvy; //rotate vector
rvx = vx*cos(theta)-vy*sin(theta);
rvy = vx*sin(theta)+vy*cos(theta);
v[0].x = A.x+rvx*A.r/disAB;
v[0].y = A.y+rvy*A.r/disAB;
rvx = vx*cos(-theta)-vy*sin(-theta);
rvy = vx*sin(-theta)+vy*cos(-theta);
v[1].x = A.x+rvx*A.r/disAB;
v[1].y = A.y+rvy*A.r/disAB;
return
2;
}

int
main() {
Cir A, B;
#define eps2 5.14e-5
while(A.scan()) {
B.scan();
Pt p[2];
int
r = IntersectCir(A, B, p);
if
(r == 0)
puts("THE CIRCLES ARE THE SAME");
else if
(r < 0)
puts("NO INTERSECTION");
else if
(r == 1)
printf("(%.3lf,%.3lf)n", p[0].x+eps2, p[0].y+eps2);
else
{
sort(p, p+2);
printf("(%.3lf,%.3lf)(%.3lf,%.3lf)n", p[0].x+eps2, p[0].y+eps2, p[1].x+eps2, p[1].y+eps2);
}
}

return
0;
}

Tags: UVA Online Judge Solution, UVA OJ Solution list, UVA Problems Solution, UVA solver, UVA all problem solution list, UVA 453  code in C, UVA code in C++, UVA 453 solution in C, UVA Intersecting Circles solution

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