# UVA Solution 453 – Intersecting Circles – Volume 4

### UVA Solution 453 – Intersecting Circles – Volume 4

UVA Online Judge Solution 453 – Intersecting Circles | Volume 4

Problem Name: 453 – Intersecting Circles solution
Problem Number : UVA – 453 – Intersecting Circles solution
Online Judge : UVA Online Judge Solution
Volume: 4
Solution Language : C plus plus

### UVA Solution 453 – Intersecting Circles Code in CPP:

`#include <stdio.h>#include <math.h>#include <algorithm>using namespace std;struct Cir {    double x, y, r;    int scan() {        return scanf("%lf %lf %lf", &x, &y, &r) == 3;    }};#define eps 1e-6struct Pt {    double x, y;    bool operator<(const Pt other) const {        if(fabs(x-other.x) < eps)            return y < other.y;        return x < other.x;    }};int IntersectCir(Cir A, Cir B, Pt v[]) { // Pt v[] result buffer    double disAB = sqrt((A.x-B.x)*(A.x-B.x)+(A.y-B.y)*(A.y-B.y));    if(fabs(disAB) < eps && fabs(A.r-B.r) < eps) {        if(A.r < eps) {            v[0].x = A.x;            v[0].y = A.y;            return 1;        }        return 0;    }    if(A.r+B.r+eps < disAB || A.r+disAB+eps < B.r || B.r+disAB+eps < A.r) {        return -1;    }    double x, y, vx, vy;    vx = B.x - A.x;    vy = B.y - A.y;    if(fabs(disAB-A.r-B.r) < eps || fabs(A.r-disAB-B.r) < eps ||       fabs(B.r-A.r-disAB) < eps) {        if(fabs(disAB-A.r-B.r) < eps) { // (A)(B)            v[0].x = A.x+vx*A.r/(A.r+B.r);            v[0].y = A.y+vy*A.r/(A.r+B.r);        } else {            if(A.r < B.r) { //((A)B)                v[0].x = A.x-vx*A.r/(B.r-A.r);                v[0].y = A.y-vy*A.r/(B.r-A.r);            } else { //((B)A)                v[0].x = B.x+vx*B.r/(A.r-B.r);                v[0].y = B.y+vy*B.r/(A.r-B.r);            }        }        return 1;    }    double theta = acos((A.r*A.r+disAB*disAB-B.r*B.r)/2/A.r/disAB);    double rvx, rvy; //rotate vector    rvx = vx*cos(theta)-vy*sin(theta);    rvy = vx*sin(theta)+vy*cos(theta);    v[0].x = A.x+rvx*A.r/disAB;    v[0].y = A.y+rvy*A.r/disAB;    rvx = vx*cos(-theta)-vy*sin(-theta);    rvy = vx*sin(-theta)+vy*cos(-theta);    v[1].x = A.x+rvx*A.r/disAB;    v[1].y = A.y+rvy*A.r/disAB;    return 2;}int main() {    Cir A, B;#define eps2 5.14e-5    while(A.scan()) {        B.scan();        Pt p[2];        int r = IntersectCir(A, B, p);        if(r == 0)            puts("THE CIRCLES ARE THE SAME");        else if(r < 0)            puts("NO INTERSECTION");        else if(r == 1)            printf("(%.3lf,%.3lf)n", p[0].x+eps2, p[0].y+eps2);        else {            sort(p, p+2);            printf("(%.3lf,%.3lf)(%.3lf,%.3lf)n", p[0].x+eps2, p[0].y+eps2, p[1].x+eps2, p[1].y+eps2);        }    }    return 0;}`

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