URI Online Judge Solution 1195 Binary Search Tree – Solution in C, C++, Java, Python and C#

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URI Online Judge Solution 1195 Binary Search Tree – Solution in C, C++, Java, Python and C#

URI Online Judge Solution 1195 Binary Search Tree  | Beginner
URI Problem Link – https://www.urionlinejudge.com.br/judge/en/problems/view/1195

Problem Name: 1195 Binary Search Tree solution
Problem Number : URI – 1195 Binary Search Tree code
Online Judge : URI Online Judge Solution
Category: Beginner
Solution Language : C,C plus plus, java, python, c#(c sharp)

URI Online Judge Solution 1195 Binary Search Tree - Solution in C, C++, Java, Python and C#

URI Problem 1195 simple input output

Input Sample Output Sample
2
3
5 2 7
9
8 3 10 14 6 4 13 7 1
Case 1:
Pre.: 5 2 7
In..: 2 5 7
Post: 2 7 5

Case 2:
Pre.: 8 3 1 6 4 7 10 14 13
In..: 1 3 4 6 7 8 10 13 14
Post: 1 4 7 6 3 13 14 10 8

URI Solution 1195 Binary Search Tree  Code in C / URI 1195 code in cpp:

#include <cstdio>
using namespace std;

struct Node
{
int data;
Node* left;
Node* right;
};

Node* GetNewroot(int data)
{
Node* newroot = new Node();
newroot -> data = data;
newroot -> left = NULL;
newroot -> right = NULL;
return newroot;
}

Node* Insert(Node* root, int data)
{
if(root == NULL){ //empty tree
root = GetNewroot(data);
return root;
}else if(data <= root -> data){
root -> left = Insert(root -> left, data);
}else{
root -> right = Insert(root -> right, data);
}

return root;
}

void printPreOrder(struct Node* root)
{
if (root == NULL)
return;
printf(" %i", root -> data);
printPreOrder (root -> left);
printPreOrder (root -> right);
}

void printInOrder(struct Node* root)
{
if (root == NULL)
return;
printInOrder (root -> left);
printf(" %i", root -> data);
printInOrder (root -> right);
}

void printPosOrder(struct Node* root)
{
if (root == NULL)
return;
printPosOrder (root -> left);
printPosOrder (root -> right);
printf(" %i", root -> data);
}

int main()
{
int c, n, x, count = 1;

scanf("%i", &c);

for (int i = 0; i < c; ++i)
{
Node* root = NULL;
scanf("%i", &n);

for (int j = 0; j < n; ++j)
{
scanf("%i", &x);
root = Insert(root, x);
}

printf("Case %i:n", count);
printf("Pre.:");
printPreOrder(root);
printf("n");

printf("In..:");
printInOrder(root);
printf("n");

printf("Post:");
printPosOrder(root);
printf("n");

count++;
//if(i != (c - 1))
printf("n");
}

return 0;
}

URI Solution 1195 Binary Search Tree  Code / URI 1195 solution in CPP:

URI Solution 1195 Binary Search Tree  Code / URI 1195 solution in Java:

URI Solution 1195 Binary Search Tree  Code / URI 1195 solution in  Python:

URI Solution 1195 Binary Search Tree  Code / URI 1195 solution in  C# (C Sharp):

Demonstration:

Just implement this in coding. Since having any problem just put a comment below. Thanks

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