URI Online Judge Solution 1071 Sum of Consecutive Odd Numbers I – Solution in C, C++, Java, Python and C#

URI Online Judge Solution 1071 Sum of Consecutive Odd Numbers I – Solution in C, C++, Java, Python and C#

URI Online Judge Solution 1071 Sum of Consecutive Odd Numbers I | Beginner
URI Problem Link – https://www.urionlinejudge.com.br/judge/en/problems/view/1071

Problem Name: 1071 Sum of Consecutive Odd Numbers I
Problem Number : URI – 1071 Sum of Consecutive Odd Numbers I
Online Judge : URI Online Judge Solution
Category: Beginner
Solution Language : C,C plus plus, java, python, c#(c sharp)

URI Solution 1071 Sum of Consecutive Odd Numbers I Code in C:

#include <stdio.h>

int main()
{
 int x, y, tmp = 0, i;
 int min, max;

 scanf("%d%d", &x,&y);

 if(x < y){
  min = x;
  max = y;
 }else{
  max = x;
  min = y;
 }

 for(i = (min + 1); i < max; ++i)
 {
  if(i % 2 == 1 || i % 2 == -1){
   tmp += i;
  }
 }

 printf("%dn", tmp);

 return 0;
}

URI Solution 1071 Sum of Consecutive Odd Numbers I Code / URI 1071 solution in CPP:

#include <iostream>

using namespace std;

int main()
{
 int x, y, tmp = 0;
 int min, max;
 
 cin >> x >> y;
 
 if(x < y){
  min = x;
  max = y;
 }else{
  max = x;
  min = y;
 }
 
 for(int i = (min + 1); i < max; ++i)
 {
  if(i % 2 == 1 || i % 2 == -1){
   tmp += i;
  }
 }
 
 cout << tmp << endl;
 
 return 0;
}

/*
    6 -5  5
    15 12  13
 */
import java.util.Scanner;

public class Main {

 public static void main(String[] args) {
  int X, Y, total = 0;
  Scanner input =new Scanner(System.in);
  X = input.nextInt();
  Y = input.nextInt();

  if (X > Y) {
   for (int i = X - 1; i > Y; i--) {
    if (i % 2 != 0) {
     total += i;
    }
   }
  }else {
   for (int i = Y - 1; i > X; i--) {
    if (i % 2 != 0) {
     total += i;
    }
   }
  }

  System.out.print(total+"n");

 }

}

URI Solution 1071 Sum of Consecutive Odd Numbers I Code / URI 1071 solution in  C# (C Sharp):

Demonstration:

Just implement this in coding. Since having any problem just put a comment below. Thanks

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