URI Online Judge Solution 1051 Taxes – Solution in C, C++, Java, Python and C#

URI Online Judge Solution URI Solution -Beginner

URI Online Judge Solution 1051 Taxes – Solution in C, C++, Java, Python and C#

URI Online Judge Solution 1051 Taxes  | Beginner
URI Problem Link – https://www.urionlinejudge.com.br/judge/en/problems/view/1051

Problem Name: 1051 Taxes Code

Problem Number : URI – 1051 Taxes Solution
Online Judge : URI Online Judge Solution
Category: Beginner
Solution Language : C,C plus plus, java, python, c#(c sharp)

URI Online Judge Solution 1051 Taxes - Solution in C, C++, Java, Python and C#

URI 1051 Taxes  Code in C / URI 1051 solution in C:

#include <stdio.h>
int main()
{

float
n, r, f1, f2, f3;
scanf("%f", &n);

if
(n <= 2000){
printf("Isenton");
}
else{
if
(n > 2000 && n <= 3000){
f1 = n - 2000;
f1 = ((f1 * 8) / 100);
r = f1;
}
else if(n > 3000 && n <= 4500){
f1 = n - 2000;
f2 = f1 - 1000;
f1 -= f2;
f1 = ((f1 * 8) / 100);
f2 = ((f2 * 18) / 100);
r = f2 + f1;
}
else{
f1 = n - 2000;
f2 = f1 - 1000;
f3 = f2 - 1500;
f1 -= f2;
f2 -= f3;
f1 = ((f1 * 8) / 100);
f2 = ((f2 * 18) / 100);
f3 = ((f3 * 28) / 100);
r = f3 + f2 + f1;
}


printf("R$ %.2fn", r);
}


return
0;
}

URI 1051 Taxes  Code in C++ / URI 1051 solution in CPP:

#include <iostream>
#include <iomanip>
using namespace std;

int
main()
{

float
n, r, f1, f2, f3;
cin >> n;

if
(n <= 2000){
cout << "Isento" << endl;
}
else{
if
(n > 2000 && n <= 3000){
f1 = n - 2000;
f1 = ((f1 * 8) / 100);
r = f1;
}
else if(n > 3000 && n <= 4500){
f1 = n - 2000;
f2 = f1 - 1000;
f1 -= f2;
f1 = ((f1 * 8) / 100);
f2 = ((f2 * 18) / 100);
r = f2 + f1;
}
else{
f1 = n - 2000;
f2 = f1 - 1000;
f3 = f2 - 1500;
f1 -= f2;
f2 -= f3;
f1 = ((f1 * 8) / 100);
f2 = ((f2 * 18) / 100);
f3 = ((f3 * 28) / 100);
r = f3 + f2 + f1;
}


cout << "R$ " << fixed << setprecision(2) << r << endl;
}


return
0;
}

URI 1051 Taxes  Code in java/ URI 1051 solution in Java:

import java.io.IOException;
import java.util.Scanner;

public class
Main {

public static
void main(String[] args) throws IOException {

float
n, r, f1, f2, f3;
Scanner sc =new Scanner(System.in);
n = sc.nextFloat();

if
(n <= 2000){
System.out.print("Isenton");
}
else{
if
(n > 2000 && n <= 3000){
f1 = n - 2000;
f1 = ((f1 * 8) / 100);
r = f1;
}
else if(n > 3000 && n <= 4500){
f1 = n - 2000;
f2 = f1 - 1000;
f1 -= f2;
f1 = ((f1 * 8) / 100);
f2 = ((f2 * 18) / 100);
r = f2 + f1;
}
else{
f1 = n - 2000;
f2 = f1 - 1000;
f3 = f2 - 1500;
f1 -= f2;
f2 -= f3;
f1 = ((f1 * 8) / 100);
f2 = ((f2 * 18) / 100);
f3 = ((f3 * 28) / 100);
r = f3 + f2 + f1;
}

System.out.printf("R$ %.2fn",r);
}

}

}

URI 1051 Taxes  Code in Python / URI 1051 solution in Python:

salario = float(raw_input())

if
(salario > 0 and salario <= 2000):
print "Isento"
elif(salario > 2000 and salario <= 3000):
resto = salario - 2000
resultado = resto * 0.08
print "R$ %.2f" %resultado
elif(salario > 3000 and salario < 4500):
resto = salario - 3000
resultado = (resto * 0.18) + (1000 * 0.08)
print "R$ %.2f" %resultado
else
:
resto = salario - 4500
resultado = (resto * 0.28) + (1500 * 0.18) + (1000 * 0.08)
print "R$ %.2f" %resultado

URI Solution 1051 Taxes  Code / URI 1051 solution in  C# (C Sharp):

Demonstration:

Just implement this in coding. Since having any problem just put a comment below. Thanks

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