URI Online Judge Solution 1051 Taxes – Solution in C, C++, Java, Python and C#

URI Online Judge Solution 1051 Taxes – Solution in C, C++, Java, Python and C#

URI Online Judge Solution 1051 Taxes  | Beginner
URI Problem Link – https://www.urionlinejudge.com.br/judge/en/problems/view/1051

Problem Name: 1051 Taxes Code

Problem Number : URI – 1051 Taxes Solution
Online Judge : URI Online Judge Solution
Category: Beginner
Solution Language : C,C plus plus, java, python, c#(c sharp)

URI 1051 Taxes  Code in C / URI 1051 solution in C:

#include <stdio.h>
int main()
{
 float n, r, f1, f2, f3;
 scanf("%f", &n);

 if(n <= 2000){
  printf("Isenton");
 }else{
  if(n > 2000 && n <= 3000){
   f1 = n - 2000;
   f1 = ((f1 * 8) / 100);
   r = f1;
  }else if(n > 3000 && n <= 4500){
   f1 = n - 2000;
   f2 = f1 - 1000;
   f1 -= f2;
   f1 = ((f1 * 8) / 100);
   f2 = ((f2 * 18) / 100);
   r = f2 + f1;
  }else{
   f1 = n - 2000;
   f2 = f1 - 1000;
   f3 = f2 - 1500;
   f1 -= f2;
   f2 -= f3;
   f1 = ((f1 * 8) / 100);
   f2 = ((f2 * 18) / 100);
   f3 = ((f3 * 28) / 100);
   r = f3 + f2 + f1;
  }

  printf("R$ %.2fn", r);
 }

 return 0;
}

URI 1051 Taxes  Code in C++ / URI 1051 solution in CPP:

#include <iostream>
#include <iomanip>
using namespace std;

int main()
{
 float n, r, f1, f2, f3;
 cin >> n;

 if(n <= 2000){
  cout << "Isento" << endl;
 }else{
  if(n > 2000 && n <= 3000){
   f1 = n - 2000;
   f1 = ((f1 * 8) / 100);
   r = f1;
  }else if(n > 3000 && n <= 4500){
   f1 = n - 2000;
   f2 = f1 - 1000;
   f1 -= f2;
   f1 = ((f1 * 8) / 100);
   f2 = ((f2 * 18) / 100);
   r = f2 + f1;
  }else{
   f1 = n - 2000;
   f2 = f1 - 1000;
   f3 = f2 - 1500;
   f1 -= f2;
   f2 -= f3;
   f1 = ((f1 * 8) / 100);
   f2 = ((f2 * 18) / 100);
   f3 = ((f3 * 28) / 100);
   r = f3 + f2 + f1;
  }

  cout << "R$ " << fixed << setprecision(2) << r << endl;
 }

 return 0;
}

import java.io.IOException;
import java.util.Scanner;

public class Main {
 
    public static void main(String[] args) throws IOException {
 
        float n, r, f1, f2, f3;
  Scanner sc =new Scanner(System.in);
  n = sc.nextFloat();
  
 if(n <= 2000){
   System.out.print("Isenton");
  }else{
   if(n > 2000 && n <= 3000){
    f1 = n - 2000;
    f1 = ((f1 * 8) / 100);
    r = f1;
   }else if(n > 3000 && n <= 4500){
    f1 = n - 2000;
    f2 = f1 - 1000;
    f1 -= f2;
    f1 = ((f1 * 8) / 100);
    f2 = ((f2 * 18) / 100);
    r = f2 + f1;
   }else{
    f1 = n - 2000;
    f2 = f1 - 1000;
    f3 = f2 - 1500;
    f1 -= f2;
    f2 -= f3;
    f1 = ((f1 * 8) / 100);
    f2 = ((f2 * 18) / 100);
    f3 = ((f3 * 28) / 100);
    r = f3 + f2 + f1;
   }
   System.out.printf("R$ %.2fn",r);
  }
 
    }
 
}

salario = float(raw_input())

if(salario > 0 and salario <= 2000):
 print "Isento"
elif(salario > 2000 and salario <= 3000):
 resto = salario - 2000
 resultado = resto * 0.08
 print "R$ %.2f" %resultado
elif(salario > 3000 and salario < 4500):
 resto = salario - 3000
 resultado = (resto * 0.18) + (1000 * 0.08)
 print "R$ %.2f" %resultado
else:
 resto = salario - 4500
 resultado = (resto * 0.28) + (1500 * 0.18) + (1000 * 0.08)
 print "R$ %.2f" %resultado

URI Solution 1051 Taxes  Code / URI 1051 solution in  C# (C Sharp):

Demonstration:

Just implement this in coding. Since having any problem just put a comment below. Thanks

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