URI Online Judge Solution 1035 Selection Test 1 – URI 1035 Solution in C, C++, Java, Python and C#

URI Online Judge Solution URI Solution -Beginner

URI Online Judge Solution 1035 Selection Test 1 – URI 1035 Solution in C, C++, Java, Python and C#

URI Online Judge Solution 1035 Selection Test 1 | Beginner
URI Problem Link – https://www.urionlinejudge.com.br/judge/en/problems/view/1035
Problem Name: 1035 Selection Test 1 code
Problem Number : URI – 1035 Selection Test 1 solution
Online Judge : URI Online Judge Solution
Category: Beginner
Solution Language : C,C plus plus, java, python, c#(c sharp)

URI Online Judge Solution 1035 Selection Test 1 - URI 1035 Solution in C, C++, Java, Python and C#
URI Online Judge Solution 1035 Selection Test 1 – URI 1035 Solution in C, C++, Java, Python and C#

URI Solution 1035 Selection Test 1 Code in C / URI 1035 code in C:

#include <stdio.h>

int
main()
{

int
a, b, c, d;
scanf("%d %d %d %d", &a, &b, &c, &d);

if
((b > c) && (d > a) && (c + d > a + b) && c > 0 && c > 0 && (a % 2 == 0))
printf("Valores aceitosn");
else

printf("Valores nao aceitosn");

return
0;
}

URI Solution 1035 Selection Test 1 Code / URI 1035 Selection Test 1 solution in CPP:

Dynamic system:

#include <cstdio>

#define SC4(a, b, c, d) scanf("%d %d %d %d", &a, &b, &c, &d)

using namespace
std;

int
main(int argc, char const *argv[])
{

int
a, b, c, d;
SC4(a, b, c, d);

if
((b > c) && (d > a) && (c + d > a + b) && c > 0 && c > 0 && (a % 2 == 0))
puts("Valores aceitos");
else

puts("Valores nao aceitos");

return
0;
}

URI Solution 1035 Code / URI 1035 solution in Java:

import java.util.Scanner;


public class
Main {

public static
void main(String[] args) {
int
a, b, c, d;
Scanner sc = new Scanner(System.in);
a = sc.nextInt();
b = sc.nextInt();
c = sc.nextInt();
d = sc.nextInt();

if
((b > c) && (d > a) && (c + d > a + b) && c > 0 && c > 0 && (a % 2 == 0))
System.out.printf("Valores aceitosn");
else

System.out.printf("Valores nao aceitosn");

}

}

URI Solution 1035 Code / URI 1035 solution in  Python:

URI Solution 1035 Code / URI 1035 solution in  C# (C Sharp):

Demonstration:

Just implement this in coding. Since having any problem just put a comment below. Thanks

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