URI Online Judge Solution 1021 Banknotes and Coins – URI 1021 Solution in C, C++, Java, Python and C#

URI Online Judge Solution URI Solution -Beginner
Maniruzzaman AkashLeave a Comment on URI Online Judge Solution 1021 Banknotes and Coins – URI 1021 Solution in C, C++, Java, Python and C#

URI Online Judge Solution 1021 Banknotes and Coins – URI 1021 Solution in C, C++, Java, Python and C#

URI Online Judge Solution 1021 Banknotes and Coins | Beginner
URI Problem Link – URI 1021 Banknotes and Coins Problem – https://www.urionlinejudge.com.br/judge/en/problems/view/1021

Problem Name: 1021 Banknotes and Coins code
Problem Number : URI – 1021 Banknotes and Coins solution
Online Judge : URI Online Judge Solution
Category: Beginner
Solution Language : C,C plus plus, java, python, c#(c sharp)

URI Online Judge Solution 1021 Banknotes and Coins - URI 1021 Solution in C, C++, Java, Python and C#

URI Solution 1021 Banknotes and Coins Code in C / URI 1021 solution in C:


#include <stdio.h>

int main() {
    int n100, n50, n20, n10, n5, n2;
    int m1, m50, m25, m10, m05, m01;
    double n;

    scanf("%lf", &n);
    int notas = n;
    int moedas = (n - notas) * 100;

    if((moedas * 1000) % 10 == 9){
        moedas++;
    }


    n100 = notas/100;
    notas = notas%100;
    n50 = notas/50;
    notas = notas%50;
    n20 = notas/20;
    notas = notas%20;
    n10 = notas/10;
    notas = notas%10;
    n5 = notas/5;
    notas = notas%5;
    n2 = notas/2;
    notas = notas%2;

    m1 = notas/1;
    notas = notas%1;
    m50 = moedas/50;
    moedas = moedas%50;
    m25 = moedas/25;
    moedas = moedas%25;
    m10 = moedas/10;
    moedas = moedas%10;
    m05 = moedas/5;
    moedas = moedas%5;
    m01 = moedas/1;

    printf("NOTAS:n");

    printf("%d nota(s) de R$ 100.00n", n100);
    printf("%d nota(s) de R$ 50.00n", n50);
    printf("%d nota(s) de R$ 20.00n", n20);
    printf("%d nota(s) de R$ 10.00n", n10);
    printf("%d nota(s) de R$ 5.00n", n5);
    printf("%d nota(s) de R$ 2.00n", n2);

    printf("MOEDAS:n");

    printf("%d moeda(s) de R$ 1.00n", m1);
    printf("%d moeda(s) de R$ 0.50n", m50);
    printf("%d moeda(s) de R$ 0.25n", m25);
    printf("%d moeda(s) de R$ 0.10n", m10);
    printf("%d moeda(s) de R$ 0.05n", m05);
    printf("%d moeda(s) de R$ 0.01n", m01);

    return 0;
}

Run Live URI 1021 C code and check [Give Test Input 576.73 to test first result]

URI Solution 1021 Banknotes and Coins Code / URI 1002 solution in CPP:

#include <iostream>
using namespace std;

int main() {
    double n100, n50, n20, n10, n5, n2;
    double m1, m50, m25, m10, m05, m01;
    double n;

    cin >> n;
    int notas = n;
    int moedas = (n - notas) * 100;

    if((moedas * 1000) % 10 == 9){
        moedas++;
    }


    n100 = notas/100;
    notas = notas%100;
    n50 = notas/50;
    notas = notas%50;
    n20 = notas/20;
    notas = notas%20;
    n10 = notas/10;
    notas = notas%10;
    n5 = notas/5;
    notas = notas%5;
    n2 = notas/2;
    notas = notas%2;

    m1 = notas/1;
    notas = notas%1;
    m50 = moedas/50;
    moedas = moedas%50;
    m25 = moedas/25;
    moedas = moedas%25;
    m10 = moedas/10;
    moedas = moedas%10;
    m05 = moedas/5;
    moedas = moedas%5;
    m01 = moedas/1;

    cout << "NOTAS:" << endl; 
    cout << n100 << " nota(s) de R$ 100.00" << endl;
    cout << n50 << " nota(s) de R$ 50.00" << endl;
    cout << n20 << " nota(s) de R$ 20.00" << endl;
    cout << n10 << " nota(s) de R$ 10.00" << endl;
    cout << n5 << " nota(s) de R$ 5.00" << endl;
    cout << n2 << " nota(s) de R$ 2.00" << endl;
    cout << "MOEDAS:" << endl;
    cout << m1 << " moeda(s) de R$ 1.00" << endl;
    cout << m50 << " moeda(s) de R$ 0.50" << endl;
    cout << m25 << " moeda(s) de R$ 0.25" << endl;
    cout << m10 << " moeda(s) de R$ 0.10" << endl;
    cout << m05 << " moeda(s) de R$ 0.05" << endl;
    cout << m01 << " moeda(s) de R$ 0.01" << endl;

    return 0;
}

URI Solution 1021 Banknotes and Coins Code / URI 1021 Banknotes and Coins solution in Java:

import java.util.Scanner;

public class Main
{

    public static void main(String[] args)
    {
        float x;
        int note100,note50,note20,note10,note5,note2;
        int moeda1,moeda5,moeda25,moeda10,moeda05,moeda01;
        int reminder100;
        Scanner input=new Scanner(System.in);
        x = input.nextFloat();
        note100 =(int) x / 100;
        reminder100 = (int) (x % 100);
        note50 = (reminder100) / 50;
        note20 = (reminder100 % 50 )/ 20;
        note10 = ((reminder100 % 50 )% 20) / 10;
        note5 = (((reminder100 % 50 )% 20) % 10) / 5;
        note2 = (((reminder100 % 50 )% 20) % 5) / 2;

        //------     MOEDAS:    ------------//
        moeda1 =  (((((reminder100 % 50 )% 20) % 5) % 2) / 1);
        float reminderMoeda = (float) (((((reminder100 % 50 )% 20) % 5) % 2));

        float meda5Float = (float) ((reminderMoeda % 1) / .5);
        moeda5 = (int) (meda5Float);

        moeda25 = (int) (((((((reminder100 % 50 )% 20) % 5) % 2) % 1) % .5) / .25);
        moeda10 = (int) ((((((((reminder100 % 50 )% 20) % 5) % 2) % 1) % .5) % .25) / .1);
        moeda05 = (int) (((((((((reminder100 % 50 )% 20) % 5) % 2) % 1) % .5) % .25) % .1) / .05);
        moeda01 = (int) ((((((((((reminder100 % 50 )% 20) % 5) % 2) % 1) % .5) % .25) % .1) % .05) / .01);


        System.out.print("NOTAS:n");
        System.out.print(note100 +" nota(s) de R$ 100.00n");
        System.out.print(note50 +" nota(s) de R$ 50.00n");
        System.out.print(note20 +" nota(s) de R$ 20.00n");
        System.out.print(note10 +" nota(s) de R$ 10.00n");
        System.out.print(note5 +" nota(s) de R$ 5.00n");
        System.out.print(note2 +" nota(s) de R$ 2.00nn");

        System.out.print("MOEDAS:n");
        System.out.print(moeda1 +" moeda(s) de R$ 1.00n");
        System.out.print(meda5Float +" moeda(s) de R$ 0.50n");
        System.out.print(moeda25 +" moeda(s) de R$ 0.25n");
        System.out.print(moeda10 +" moeda(s) de R$ 0.10n");
        System.out.print(moeda05 +" moeda(s) de R$ 0.05n");
        System.out.print(moeda01 +" moeda(s) de R$ 0.01n");

    }

}

URI Solution 1021Code / URI 1021 Banknotes and Coins solution in  Python:

value = eval(input());

cem = cinquenta = vinte = dez = cinco = dois = um = 0;
cincents = vintecincents = dezcents = cincocents = cents = 0;

value = float("%.2f" % value)
if int(value/100) >= 1:
 cem = int(value/100);
 value -= cem*100;

value = float("%.2f" % value)
if int(value/50) >= 1:
 cinquenta = int(value/50);
 value -= cinquenta*50;

value = float("%.2f" % value)
if int(value/20) >= 1:
 vinte = int(value/20.00);
 value -= vinte*20;

value = float("%.2f" % value)
if int(value/10) >= 1:
 dez = int(value/10);
 value -= dez*10.00;

value = float("%.2f" % value)
if int(value/5) >= 1:
 cinco = int(value/5);
 value -= cinco*5;

value = float("%.2f" % value)
if int(value/2) >= 1:
 dois = int(value/2);
 value -= dois*2;

value = float("%.2f" % value)
if int(value/1) >= 1:
 um = int(value/1);
 value -= um*1;

value = float("%.2f" % value)
if int(value/0.50) >= 1:
 cincents = int(value/0.50);
 value -= cincents*0.50;

value = float("%.2f" % value)
if int(value/0.25) >= 1:
 vintecincents = int(value/0.25);
 value -= vintecincents*0.25;

value = float("%.2f" % value)
if int(value/0.10) >= 1:
 dezcents = int(value/0.10);
 value -= dezcents*0.10;

value = float("%.2f" % value)
if int(value/0.05) >= 1:
 cincocents = int(value/0.05);
 value -= cincocents*0.05;

value = float("%.2f" % value)
if int(value/0.01) >= 0.998:
 cents = int(value/0.01);
 value -= cents*0.01;

print("NOTAS:");
print("%d nota(s) de R$ 100.00" % cem);
print("%d nota(s) de R$ 50.00" % cinquenta);
print("%d nota(s) de R$ 20.00" % vinte);
print("%d nota(s) de R$ 10.00" % dez);
print("%d nota(s) de R$ 5.00" % cinco);
print("%d nota(s) de R$ 2.00" % dois);

print("MOEDAS:");
print("%d moeda(s) de R$ 1.00" % um);
print("%d moeda(s) de R$ 0.50" % cincents);
print("%d moeda(s) de R$ 0.25" % vintecincents);
print("%d moeda(s) de R$ 0.10" % dezcents);
print("%d moeda(s) de R$ 0.05" % cincocents);
print("%d moeda(s) de R$ 0.01" % cents);

URI Solution 1021Code / URI 1021 Banknotes and Coins solution in  C# (C Sharp):

Demonstration:

It’s a problem of URI online Judge to convert notes. Use reminder to get the notes part and try..
Just implement this in coding. Since having any problem just put a comment below. Thanks

Tags: URI Online Judge Solution, URI OJ Solution list, URI Problems Solution, URI solver, URI all problem solution list, URI Banknotes and Coins code in C, URI 1021 code in C++, URI Banknotes and Coins solution in C, URI solution, URI 1021 Banknotes and Coins solution in C,URI 1021 Banknotes and Coins solution in C++-CPP,URI 1021 solution in C# (C sharp),URI 1021 Banknotes and Coins solution in Java,URI 1021 Banknotes and Coins solution in Python,

Related Posts

URI Online Judge Solution 1013 The Greatest – URI 1013 solution in C, C++, Java, Python and C#

Maniruzzaman Akash

URI Online Judge Solution 1038 Snack – Solution in C, C++, Java, Python and C#

Maniruzzaman Akash

URI Online Judge Solution SQL | 2606 Categories – PostGreSQL Solution – Code

Maniruzzaman Akash

Leave a Reply

Your email address will not be published. Required fields are marked *