URI Online Judge Solution 1018 Banknotes – URI 1018 Solution in C, C++, Java, Python and C#

URI Online Judge Solution URI Solution -Beginner

URI Online Judge Solution 1018 Banknotes – URI 1018 Solution in C, C++, Java, Python and C#

URI Online Judge Solution 1018 | Beginner
URI Problem Link – https://www.urionlinejudge.com.br/judge/en/problems/view/1018

Problem Name: URI 1018 code
Problem Number : URI – 1018 Banknotes solution
Online Judge : URI Online Judge Solution
Category: Beginner
Solution Language : C,C plus plus, java, python, c#(c sharp)

URI Online Judge Solution 1018 Banknotes - URI 1018 Solution in C, C++, Java, Python and C#

URI Solution 1018 Banknotes Code in C / URI 1018 solution in C:

#include <stdio.h>


int
main(){
int
notes, aux;

scanf("%d", &notes);

printf("%dn", notes);
printf("%d nota(s) de R$ 100,00n", notes/100);
aux = (notes%100);


printf("%d nota(s) de R$ 50,00n", aux/50);
aux = (aux%50);

    printf("%d nota(s) de R$ 20,00n", aux/20);
aux = (aux%20);

    printf("%d nota(s) de R$ 10,00n", aux/10);
aux = (aux%10);

    printf("%d nota(s) de R$ 5,00n", aux/5);
aux = (aux%5);

    printf("%d nota(s) de R$ 2,00n", aux/2);
aux = (aux%2);

    printf("%d nota(s) de R$ 1,00n", aux/1);
return
0;
}

URI Solution 1018 Banknotes Code / URI 1018 Banknotes solution in CPP:

#include <iostream>

using namespace
std;

int
main(){
int
inteiro, aux;

cin >> inteiro;

cout << inteiro <<"n";
cout << inteiro/100 << " nota(s) de R$ 100,00n";
    aux = (inteiro%100);
    cout << aux/50 << " nota(s) de R$ 50,00n";
aux = (aux%50);
    cout << aux/20 << " nota(s) de R$ 20,00n";
aux = (aux%20);
    cout << aux/10 << " nota(s) de R$ 10,00n";
aux = (aux%10);
    cout << aux/5 << " nota(s) de R$ 5,00n";
aux = (aux%5);
    cout << aux/2 << " nota(s) de R$ 2,00n";
aux = (aux%2);
    cout << aux/1 << " nota(s) de R$ 1,00n";
return
0;
}

URI Solution 1018 Banknotes Code / URI 1018 Banknotes solution in Java:

import java.util.Scanner;


public class
Main {

public static
void main(String[] args) {
int
notes, aux;

Scanner sc = new Scanner(System.in);
notes = sc.nextInt();

System.out.printf("%dn", notes);
System.out.printf("%d nota(s) de R$ 100,00n", notes/100);
aux = (notes%100);


System.out.printf("%d nota(s) de R$ 50,00n", aux/50);
aux = (aux%50);

System.out.printf("%d nota(s) de R$ 20,00n", aux/20);
aux = (aux%20);

System.out.printf("%d nota(s) de R$ 10,00n", aux/10);
aux = (aux%10);

System.out.printf("%d nota(s) de R$ 5,00n", aux/5);
aux = (aux%5);

System.out.printf("%d nota(s) de R$ 2,00n", aux/2);
aux = (aux%2);

System.out.printf("%d nota(s) de R$ 1,00n", aux/1);

}

}

URI Solution 1018 Banknotes Code / URI 1018 Banknotes solution in  Python:

URI Solution 1018 Banknotes Code / URI 1018 Banknotes solution in  C# (C Sharp):

Demonstration:

Just implement this in coding. Since having any problem just put a comment below. Thanks

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