# URI Online Judge Solution 1015 Distance Between Two Points – URI 1015 Solution in C, C++, Java, Python and C#

### URI Online Judge Solution 1015 Distance Between Two Points – URI 1015 Solution in C, C++, Java, Python and C#

URI Online Judge Solution 1015 Distance Between Two Points | Beginner

Problem Name: 1015 Distance Between Two Points solution
Problem Number : URI – 1015 Distance Between Two Points code
Online Judge : URI Online Judge Solution
Category: Beginner
Solution Language : C,C plus plus, java, python, c#(c sharp)

### URI Solution 1015 Distance Between Two Points Code in C / URI 1015 code in C:

`#include <stdio.h>#include <math.h>int main(){ double x1, x2, y1, y2, dist; scanf("%lf %lf %lf %lf", &x1, &y1, &x2, &y2); dist = sqrt(pow(x2-x1,2)+pow(y2-y1,2)); printf("%.4lfn", dist); return 0;}`

### URI Solution 1015 Distance Between Two Points Code / URI 1015 solution in CPP:

`#include <stdio.h>#include <math.h>int main(){ double x1, x2, y1, y2, dist; scanf("%lf %lf %lf %lf", &x1, &y1, &x2, &y2); dist = sqrt(pow(x2-x1,2)+pow(y2-y1,2)); printf("%.4lfn", dist); return 0;}`

### URI Solution 1015 Distance Between Two Points Code / URI 1015 solution in Java:

`import java.util.Scanner;public class Main { public static void main(String[] args) {  double x1, x2, y1, y2, dist;  Scanner sc = new Scanner(System.in);  x1 = sc.nextDouble();  y1 = sc.nextDouble();  x2 = sc.nextDouble();  y2 = sc.nextDouble();  dist = Math.sqrt(Math.pow(x2-x1,2)+Math.pow(y2-y1,2));  System.out.printf("%.4fn", dist); }}`

### URI Solution 1015 Distance Between Two Points Code / URI 1015 solution in  Python:

`import mathlinha1 = input().split(" ")linha2 = input().split(" ")x1,y1 = linha1x2,y2 = linha2distancia = math.sqrt(((float(x2) - float(x1))*(float(x2) - float(x1))) + ((float(y2)-float(y1)) *(float(y2)-float(y1))))print("%0.4f" %distancia)`

### URI Solution 1015 Code / URI 1015 solution in  C# (C Sharp):

Demonstration:

Look for this problems , So, our code is:

`        scanf("%lf %lf %lf %lf", &x1, &y1, &x2, &y2); dist = sqrt(pow(x2-x1,2)+pow(y2-y1,2));`

Just implement this in coding. Since having any problem just put a comment below. Thanks

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