URI Online Judge Solution 1010 Simple Calculate – URI 1010 Solution in C, C++, Java, Python and C#

URI Online Judge Solution URI Solution -Beginner

URI Online Judge Solution 1010 Simple Calculate – URI 1010 Solution in C, C++, Java, Python and C#

URI Online Judge Solution 1010 Simple Calculate | Beginner
URI Problem Link – https://www.urionlinejudge.com.br/judge/en/problems/view/1010

Problem Name: 1010 Simple Calculate code
Problem Number : URI – 1010 Simple Calculate solution
Online Judge : URI Online Judge Solution
Category: Beginner
Solution Language : C,C plus plus, java, python, c#(c sharp)

URI Online Judge Solution 1010 Simple Calculate - URI 1010 Solution in C, C++, Java, Python and C#

URI Solution 1010 Simple Calculate Code/ URI 1010 solution in C:

Simple sense URI 1010 code in C without array
#include <stdio.h>

int
main()
{

int
a, b;
double
c, res;

scanf("%d %d %lf", &a, &b, &c);
res = b * c;
scanf("%d %d %lf", &a, &b, &c);
res += b * c;
printf("VALOR A PAGAR: R$ %.2lfn", res);

return
0;
}
URI 1010 code in C with array

#include<stdio.h>
int main()
{

int
p_code[2], p_u[2], i;
float
price[2], pay;
for
(i=0; i<2; i++)
{

scanf("%d %d %f",&p_code[i],&p_u[i],&price[i]);
}

pay=((price[0]*p_u[0])+(price[1]*p_u[1]));
printf("VALOR A PAGAR: R$ %.2fn", pay);
return
0;

}

URI Solution 1010 Simple Calculate Code / URI 1010 Simple Calculate solution in CPP:

#include <cstdio>
using namespace std;

int
main(int argc, char const *argv[])
{

int
a, b;
double
c, res;

scanf("%d %d %lf", &a, &b, &c);
res = b * c;
scanf("%d %d %lf", &a, &b, &c);
res += b * c;
printf("VALOR A PAGAR: R$ %.2lfn", res);

return
0;
}

URI Solution 1010 Simple Calculate Code / URI 1010 Simple Calculate solution in Java:

import java.util.Scanner;


public class
Main{

public static
void main(String[] args) {

int
a, b;
double
c, res;
Scanner sc = new Scanner(System.in);

a = sc.nextInt();
b = sc.nextInt();
c = sc.nextDouble();
res = b * c;

a = sc.nextInt();
b = sc.nextInt();
c = sc.nextDouble();
res += b * c;
System.out.printf("VALOR A PAGAR: R$ %.2fn", res);


}

}

URI Solution 1010 Code / URI 1010 solution in  Python:

linha1 = input().split(" ")
linha2 = input().split(" ")

cod1, qtde1, valor1 = linha1
cod2, qtde2, valor2 = linha2

total = (int(qtde1) * float(valor1)) + (int(qtde2) * float(valor2))

print("VALOR A PAGAR: R$ %0.2f" %total)

URI Solution 1010 Code / URI 1010 solution in  C# (C Sharp):

URI Online Judge Solution 1010 Code Demonstration:

First take 3 values in store it in a result variable
Again take 3 value and now just increment the result variable. And solved, in C that is

        scanf("%d %d %lf", &a, &b, &c);
res = b * c;
scanf("%d %d %lf", &a, &b, &c);
res += b * c;

Just implement this in coding. Since having any problem just put a comment below. Thanks

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