# URI Online Judge Solution 1010 Simple Calculate – URI 1010 Solution in C, C++, Java, Python and C#

### URI Online Judge Solution 1010 Simple Calculate – URI 1010 Solution in C, C++, Java, Python and C#

URI Online Judge Solution 1010 Simple Calculate | Beginner
URI Problem Link – https://www.urionlinejudge.com.br/judge/en/problems/view/1010

Problem Name: 1010 Simple Calculate code
Problem Number : URI – 1010 Simple Calculate solution
Online Judge : URI Online Judge Solution
Category: Beginner
Solution Language : C,C plus plus, java, python, c#(c sharp)

### URI Solution 1010 Simple Calculate Code/ URI 1010 solution in C:

Simple sense URI 1010 code in C without array
`#include <stdio.h>int main(){ int a, b; double c, res; scanf("%d %d %lf", &a, &b, &c); res = b * c; scanf("%d %d %lf", &a, &b, &c); res += b * c; printf("VALOR A PAGAR: R\$ %.2lfn", res); return 0;}`
URI 1010 code in C with array

`#include<stdio.h>int main(){    int p_code[2], p_u[2], i;    float price[2], pay;    for(i=0; i<2; i++)    {        scanf("%d %d %f",&p_code[i],&p_u[i],&price[i]);    }    pay=((price[0]*p_u[0])+(price[1]*p_u[1]));    printf("VALOR A PAGAR: R\$ %.2fn", pay);    return 0; }`

### URI Solution 1010 Simple Calculate Code / URI 1010 Simple Calculate solution in CPP:

`#include <cstdio>using namespace std;int main(int argc, char const *argv[]){ int a, b; double c, res; scanf("%d %d %lf", &a, &b, &c); res = b * c; scanf("%d %d %lf", &a, &b, &c); res += b * c; printf("VALOR A PAGAR: R\$ %.2lfn", res); return 0;}`

### URI Solution 1010 Simple Calculate Code / URI 1010 Simple Calculate solution in Java:

`import java.util.Scanner;public class Main{ public static void main(String[] args) {    int a, b;  double c, res;  Scanner sc = new Scanner(System.in);    a = sc.nextInt();  b = sc.nextInt();  c = sc.nextDouble();  res = b * c;    a = sc.nextInt();  b = sc.nextInt();  c = sc.nextDouble();  res += b * c;  System.out.printf("VALOR A PAGAR: R\$ %.2fn", res);     }}`

### URI Solution 1010 Code / URI 1010 solution in  Python:

`linha1 = input().split(" ")linha2 = input().split(" ")cod1, qtde1, valor1 = linha1cod2, qtde2, valor2 = linha2total = (int(qtde1) * float(valor1)) + (int(qtde2) * float(valor2))print("VALOR A PAGAR: R\$ %0.2f" %total)`

### URI Solution 1010 Code / URI 1010 solution in  C# (C Sharp):

URI Online Judge Solution 1010 Code Demonstration:

First take 3 values in store it in a result variable
Again take 3 value and now just increment the result variable. And solved, in C that is

`        scanf("%d %d %lf", &a, &b, &c); res = b * c; scanf("%d %d %lf", &a, &b, &c); res += b * c;`

Just implement this in coding. Since having any problem just put a comment below. Thanks

Tags: URI Online Judge Solution, URI OJ Solution list, URI Problems Solution, URI solver, URI all problem solution list, URI Simple Calculate  code in C, URI 1010 code in C++, URI Simple Calculate  solution in C, URI solution, URI 1010 solution in C,URI 1010 solution in C++-CPP,URI 1010 solution in C# (C sharp),URI 1010 solution in Java,URI 1010 solution in Python,

#### By Maniruzzaman Akash

Maniruzzaman Akash is a freelance web developer with most popular Laravel PHP frameork and Vue JS