# URI Online Judge Solution 1007 Difference – Solution in C, C++, Java, Python and C#

### URI Online Judge Solution 1007 Difference – Solution in C, C++, Java, Python and C#

URI Online Judge Solution 1007 Difference  | Beginner
URI Problem Link – 1007 Difference – https://www.urionlinejudge.com.br/judge/en/problems/view/1007

Problem Name: 1007 Difference solution
Problem Number : URI – 1007 Difference code
Online Judge : URI Online Judge Solution
Category: Beginner
Solution Language : C,C plus plus, java, python, c#(c sharp)
URI 1007 main problem screenshot:

If you enough time see the video of URI online judge solution 1007 –

### URI Solution 1007 Difference  Code in C/ URI 1007 solution in C:

`#include <stdio.h>int main() {     int A , B , C , D, difference;    scanf("%d %d %d %d", &A , &B ,&C, &D);    difference=((A * B) - (C * D));    printf("DIFERENCA = %dn", difference);    return 0;}`

### URI Solution 1007 Difference  Code / URI 1007 Difference  solution in CPP:

`#include <stdio.h>int main() {     int A , B , C , D, difference;    scanf("%d %d %d %d", &A , &B ,&C, &D);    difference=((A * B) - (C * D));    printf("DIFERENCA = %dn", difference);    return 0;}`

### URI Solution 1007 Difference  Code / URI 1007 Difference  solution in Java:

`import java.util.Scanner;public class Main {    public static void main(String[] args){      int A , B , C , D, difference;      Scanner sc = new Scanner(System.in);      A = sc.nextInt();      B = sc.nextInt();      C = sc.nextInt();      D = sc.nextInt();  difference=((A * B) - (C * D));  System.out.printf("DIFERENCA = %dn", difference);    }}`

### URI Solution 1007 Difference  Code / URI 1007 Difference  solution in  Python:

`a= int(input())b= int(input())c= int(input())d= int(input())difference=((a * b) - (c * d))print("DIFERENCA = %d" %difference)`

### URI Solution 1007 Difference  Code / URI 1007 Difference  solution in  C# (C Sharp):

`using System;class URI {    static void Main(string[] args) {            int a, b, c, d, difference;            a = Convert.ToInt32(Console.ReadLine());            b = Convert.ToInt32(Console.ReadLine());            c = Convert.ToInt32(Console.ReadLine());            d = Convert.ToInt32(Console.ReadLine());            difference = ((a * b) - (c * d));            Console.WriteLine("DIFERENCA = " + difference);            Console.ReadKey();    }}`

Demonstration:

We have to just get the differences and for that the equation is given in the question that – (A * B – C * D) and implement this logic in this line of C code-

`difference=((A * B) - (C * D));`

Just implement this in coding. Since having any problem just put a comment below. Thanks

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