URI Online Judge Solution 1006 Average 2 – Solution in C, C++, Java, Python and C#
URI Online Judge Solution 1006 Average 2 | Beginner
URI Problem Link -1006 Average 2 – https://www.urionlinejudge.com.br/judge/en/problems/view/1006
Problem Name: 1006 Average 2 solution
Problem Number : URI – 1006 Average 2 code
Online Judge : URI Online Judge Solution
Category: Beginner
Solution Language : C,C plus plus, java, python, c#(c sharp)
URI 1006 problem screenshot:
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| URI Online Judge Solution 1006 Average 2 – Solution in C, C++, Java, Python and C# |
URI Solution 1006 Average 2 Code in C:
#include <stdio.h>
int main()
{
double a, b, c, media;
scanf("%lf%lf%lf", &a, &b, &c);
media = (a/10 * 2) + (b/10 * 3) + (c/10 * 5);
printf("MEDIA = %.1lfn", media);
return 0;
}
URI Solution 1006 Average 2 Code C++/ URI 1006 Average 2 solution in CPP:
#include <iostream>
#include <iomanip>
using namespace std;
int main()
{
double a, b, c, media;
cin >> a >> b >> c;
media = (a/10 * 2) + (b/10 * 3) + (c/10 * 5);
cout << "MEDIA = "<< fixed << setprecision(1) << media << endl;
return 0;
}
URI Solution 1006 Average 2 Code in java / URI 1006 Average 2 solution in Java:
import java.util.Scanner;
public class Main{
public static void main(String[] args){
double a, b, c, med;
Scanner sc =new Scanner(System.in);
a =sc.nextDouble();
b =sc.nextDouble();
c =sc.nextDouble();
med = (a/10 * 2) + (b/10 * 3) + (c/10 * 5);
String media = String.format("MEDIA = %,.1f", med);
System.out.print(media +"n");
}
}
URI Solution 1006 Average 2 Code / URI 1006 Average 2 solution in Python:
a = float(input())
b = float(input())
c = float(input())
media = (a/10 * 2) + (b/10 * 3) + (c/10 * 5);
print("MEDIA = %0.5f" %media)
URI Solution 1006 Average 2 Code / URI 1006 Average 2 solution in C# (C Sharp):
using System;
class URI {
static void Main(string[] args) {
double a, b, c;
a = Convert.ToDouble(Console.ReadLine());
b = Convert.ToDouble(Console.ReadLine());
c = Convert.ToDouble(Console.ReadLine());
Console.WriteLine("MEDIA = " + ((a/10 * 2) + (b/10 * 3) + (c/10 * 5)).ToString("0.00000"));
Console.ReadKey();
}
}
Demonstration:
Since in the question, it has told that each grade has grown from 0 to 10, so devide it with 10 and multiplication into with their weight. Just main line is this,
media = (a/10 * 2) + (b/10 * 3) + (c/10 * 5);
Just implement this in coding. Since having any problem just put a comment below. Thanks
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